These marbles are placed in a bag and two of them are randomly drawn what is the probability of drawing two yellow marbles if the first one is placed back before the second draw…

Question

asked Dec 3, 2021 161k views

2 Answers

Dmitry Kabanov · Answer 1 · 2021-12-10T12:56:40+0000

Answer:

Probability of drawing two yellow marbles if the first one is placed back before the second draw is 1 : 5.

Explanation:

Given:

Number of yellow marbles = 2

Number of pink marbles = 3

Number of blue marbles = 5

Total number of marbles = 10

To Find:

Probability of drawing two yellow marbles if the first one is placed back before the second draw = ?

Solution:

Let

P(A) be the probability of drawing the first marble

P(B) be the probability of drawing the second marble.

$P(A) = \frac{\text {event occurred}}{\text{ total outcomes}}$

P(A) = (2)/(10)

Similarly

$P(B) = \frac{\text {event occurred}}{\text{ total outcomes}}$

P(B) = (2)/(10)

Since the first one is placed back before the second draw.

Now P(A) and P(B) are independent event

$P(A \text{ and }B) = P(A) \cdot P(B)$

=>
(2)/(10) * (2)/(10)

=>
(4)/(20)

=>
(2)/(10)

=>
(1)/(5)