Question

Geometry Homework
( SOH CAH TOA )
PLEASE HELP!!

Answer 1

Question 3:

AC = 3 yd.

m∠B = 37°

m∠C = 53°

Question 4;

GH = 8 km.

m∠H = 62°

m∠I = 28°

Explanation:

Question 3:

The length AC

`AC = 5*sin B.`

And the angle B

`\boxed{\angle B=cos^(-1)((4)/(5) )=36.87^o\approx 37^o.}`

Therefore

`\boxed{AC = 5*sin(37^o)= 3yd}`

And the angle C:

`\boxed{\angle C=sin^(-1)((4)/(5) )=53.13^o \approx 53^o}`

Question 4:

The side GH

`GH =17\:sin(I)`

The angle I is

`\boxed{\angle I=cos^(-1)((15)/(17) )=28.07^o\approx 28^o}`

Therefore,

`\boxed{GH =17\:sin(I)=17sin(28^o)=8km}`

And the angle H:

`\boxed{\angle H=sin^(-1)((15)/(17) )=61.927^o\approx 62^o}`