Question

A fish tank, in a shape of rectangular prism, measures

100 cm × 60 cm × 40 cm. The water level reached the
midpoint of the base (the 50 cm mark), when the tank
was tilted to rest on a 60 cm edge, as shown in the
diagram on the right. What would be the depth of the
water, if the tank is returned to its horizontal position
(resting on its 60 cm × 100 cm base)?

Answer 1

Answer:20cm

Explanation:

Answer 2

The deep of the water would be 20 cm

Explanation:

step 1

Find the volume of the water

The volume of the water is equal to

`V=LWH`

we have

`L=60\ cm\\W=40\ cm\\H=50/ cm`

substitute

`V=(60)(40)(50)`

`V=120,000\ cm^3`

step 2

Find the deep of the water, if the tank is returned to its horizontal position

(resting on its 60 cm × 100 cm base)

Now we have

`L=60\ cm\\W=100\ cm\\H=?\ cm`

`V=120,000\ cm^3`

substitute the given values

`120,000=(60)(100)H`

solve for H

`H=120,000/6,000`

`H=20\ cm`

therefore

The deep of the water would be 20 cm