The two numbers are 6 and 10
Solution:
Let "x" be the smaller number
Let "y" be the larger number
Given that difference between two numbers is 4
larger number - smaller number = 4
y - x = 4 ----- eqn 1
Also given that three times the smaller number is equal to two times the larger less two
three times smaller number = 2 times larger number less two
3x = 2y - 2 ---- eqn 2
From eqn 1,
y = 4 + x --- eqn 3
Substitute eqn 3 in eqn 2
3x = 2(4 + x) - 2
3x = 8 + 2x - 2
x = 6
From eqn 3,
y = 4 + 6 = 10
Thus the two numbers are 6 and 10