Question

Please help me out please.

Answer 1

Values of
`a=-14.14,2.47`

Explanation:

Let us find the determinant

`a(-a-40)-2(a^2-48)+1(5a+6)=0\\\\-a^2-40a-2a^2+96+5a+6=0\\\\-3a^2-35a+105=0\\\\a=(35\pm √(35^2-4* -3* 105))/(2* -3)\\\\a=(35\pm 49.84)/(-6)\\\\a=(35+ 49.84)/(-6)=-14.14\\\\or\\\\a=(35- 49.84)/(-6)=2.47`