Find the probability of making a five digit number form 2,3,4,7,8 in such a way that 7 is the first number and 8 is the last number

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asked Oct 24, 2022 26.5k views

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DavidWinterbottom · Answer 1 · 2022-10-29T22:38:03+0000

Answer:

n(E) = 6

Explanation:

That's to say that there are 6 five-digit numbers with 7 in the first place and 8 in the last place, using the digits 2, 3, 4, 7 and 8. Therefore n(E) = 6.

Find the probability of making a five digit number form 2,3,4,7,8 in such a way that 7 is the first number and 8 is the last number

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