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3. IFAB -2(x+1), BC - 3x + 1, and AC -4(x + 2), then find the value for x, AB, BC and AC.​

3. IFAB -2(x+1), BC - 3x + 1, and AC -4(x + 2), then find the value for x, AB, BC and AC.​
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3. IFAB -2(x+1), BC - 3x + 1, and AC -4(x + 2), then find the value for x, AB, BC and AC.​

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User StefMa
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1 Answer

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Answer: X=5 AB=12 BC=16 AC=28

hope this helps

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User Alexander Bell
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