Question

A liquid of specific heat 3000J/kgk rise from 15°c to 65°c in 1 min when an electric heater is used. If the heater generate 63000J, calculate the mass of the water​

Answer 1

0.42 kg

Step-by-step explanation:

Heat is proportional to mass by way of the conversion factor that is the inverse of the specific heat.

`\frac{63000\text{ J}}{\frac{3000\text{ J}}{\text{kg$\cdot$K}}\cdot(65-15)\text{ K}}=0.42\text{ kg}`

The mass of the liquid is about 0.42 kg.