Can anyone help me please

Question

asked Mar 3, 2023 196k views

2 Answers

Conor Svensson · Answer 1 · 2023-03-05T18:31:17+0000

Answer:

NM =
√(70)

Explanation:

Δ NMO and Δ KML are similar ( by the AA postulate )

Then the ratios of corresponding sides are in proportion, that is

(NM)/(KM) =
(NO)/(KL) ( substitute values, noting KL = 2NM )

(KM)/(29) =
(7)/(2NM) ( cross- multiply )

2 NM² = 140 ( divide both sides by 2 )

NM² = 70 ( take the square root of both sides )

NM =
√(70)

Sange · Answer 2 · 2023-03-07T15:18:59+0000

Answer:

NM =
$\sf √(70)$

Explanation:

Let NM = y

If KL is twice the length of NM, then KL = 2y

Given:

As ΔKLN ~ ΔNOM

KL : KM = NO : NM

$\sf \implies 2y : 20 = 7 : y$

$\sf \implies (2y)/(20)=(7)/(y)$

$\sf \implies 2y \cdot y=7 \cdot 20$

$\sf \implies 2y^2=140$

$\sf \implies y^2=70$

$\sf \implies y=√(70)$

As NM = y, then NM =
$\sf √(70)$