Question

Suppose y varies jointly as × and z. What is y when × = 2 and z = 3, if y = 20 when × = 4 and z = 3?

Answer 1

y = kxz

Explanation:

(Find K)

20 = k(4) (3)

20/12 = k

k = 5/3

(Find Y)

y = (5/3)(2)(3)

y = 10

I hope this helps.