Answer:
slope of line AB = 5 
 
Let the required line be 'l'. 
 
since AB is parallel to 'l'. 
 
so slope of 'l' = slope of AB = 5. 
 
So, the required equation of line which passes through (4,5) and having slope 5 is given by 
 
y - 5 = 5(x - 4).........[using slope point form] 
 
y = 5x - 20 + 5 
 
y = 5x - 15.
Explanation: