Question

V2 = v2. + 2 as, dimensional expression​

Answer 1

This is the third equation of motion.

`{ \rm{ {v}^(2) = {u}^(2) + 2as }}`

• Dimensions of velocity

`{ \rm{velocity = (distance)/(time) }} \\ \\ { \rm{[velocity] = (L)/(T) }} \\ \\ { \rm{{[velocity] =LT {}^( - 1) }}}`

• Dimensions of acceleration

`{ \rm{[acceleration] = LT {}^( - 2) }}`

Therefore, Answer is;

`{ \rm{LT {}^( - 1) = LT {}^( - 1) + (2 * LT {}^( - 2) * L) }} \\ \\ { \rm{LT {}^( - 1) = 2LT {}^( - 2)(T + L)}} \\ \\ { \boxed{ \rm{ \: (T)/(2) = L }}}`