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A line passes through the point (6,-1) and is perpendicular to the line with equation "-2+3y=-6" which is the equation of the line

A line passes through the point (6,-1) and is perpendicular to the line with equation "-2+3y=-6" which is the equation of the line
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a line passes through the point (6,-1) and is perpendicular to the line with equation "-2+3y=-6" which is the equation of the line

asked
User Andrei Bularca
by
8.2k points

1 Answer

2 votes

Answer:

y = 1/3x

Explanation:

answered
User Emmanuel Demey
by
8.0k points
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