A second 0.69 bullfrog is on a log tilted 26 degrees above horizontal. How large is the normal force of the log on this bullfrog?

Question

asked May 17, 2022 152k views

1 Answer

Yug Kapoor · Answer 1 · 2022-05-22T05:48:52+0000

Answer:

Below

Step-by-step explanation:

To find the normal force of the frog on the inclined plane we can use this formula :

$Fn = mgCos\alpha$

$Fn = (0.69kg)(9.8)Cos(26) \\ = 6.762 Cos(26) \\ = 6.07764 N \\ = 6.08 N$

Hope this helps!