Question

Find the zeros of f (x) = 8x^2 - 1.
The zeros are x = ___and x___​

Answer 1

x=
`√(2)`/4 and x=-
`√(2)`/4

Explanation:

One method of solving is using the Quadratic Formula: -b ±
`\sqrt{b^(2)-4ac }`/2a, with a=8, b=0, and c=-1.

After plugging these values in you get -0±
`√(0^2-(4*8*-1))`/2*8

After simplifying you get ±
`√(32)`/16

Because 32 is 2^5, you can simplify it to 4
`√(2)`, which makes the equation ±4
`√(2)`/16, or ±
`√(2)`/4.