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57²⁰¹⁸ and 51²⁰²⁰, which one is larger? (57^2018 vs 51^2020)

1 Answer

3 votes

Answer:

steps below

Explanation:

Set log x = a and log y = b

x = 10ᵃ and y = 10ᵇ

if a>b 10ᵃ > 10ᵇ

so x > y

x = 57²⁰¹⁸ y = 51²⁰²⁰

log x = log 57²⁰¹⁸ = 2018 * log 57 = 3543.36 : (a)

log y = log 51²⁰²⁰ = 2020 * log 51 = 3449.29 : (b)

3543.36 > 3449.29 log x > log y

x > y: 57²⁰¹⁸ > 51²⁰²⁰

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User Gerros
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