Question

A bag contains 2 red marbles, 6 blue marbles and 7 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest 100oth, that both marbles drawn will be red?​

Answer 1

0.01 (nearest hundredth)

Explanation:

`\mathsf{probability=(number \ of \ favorable \ outcomes)/(number \ of \ total \ outcomes)}`

Total number of marbles (total outcomes) = 2 + 6 + 7 = 15

⇒ Probability of the first marble being red =
`(2)/(15)`

As there is no replacement, the total number marbles is now 15 and there is only 1 red marble left.

⇒ Probability of the second marble being red =
`(1)/(14)`

So the probability of the 1st and 2nd marble being red is:

`(2)/(15)* (1)/(14) = (1)/(105)` = 0.01 (nearest hundredth)