Question

Can someone please help me ​

Answer 1

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Answer 2

`sin(x + y) = sinx cosy + cosxsiny = (1)/(8) \\ sin(x - y) = sinx cosy - cosx siny = (1)/(16) \\ add \: the \: above \\ 2sinx cosy =(1)/(8) + (1)/(16) \\ 2sinx cosy =(2 + 1)/(16) \\ 2sinx cosy =(3)/(16) \\ sinx cosy =(3)/(32) \\ \\ similarly \: subtract\\2cosxsiny=(1)/(16)-(1)/(8)==(2 - 1)/(16)\\\2cosxsiny=(1)/(16)\\\cosxsiny=(1)/(32)`