asked 68.4k views
2 votes
How many

solutions for x does the following equation have?
4/5(20x + 5) = 16x - 2


A. 1
B. -2
C. 0
D. infinite

How many solutions for x does the following equation have? 4/5(20x + 5) = 16x - 2 A-example-1

2 Answers

5 votes
the answer will be c zero
answered
User Erin Call
by
8.0k points
0 votes

Answer:

There are no solutions

Explanation:

4/5 ( 20x + 5 ) = 16x - 2

Distibute on the left:

( 4/5 x 20 x ) + ( 4/5 x 5 ) = 16x - 2

16x + 4 = 16x - 2

Subtract 16x from both sides:

4=-2

Add 2 to each side:

6=0

No solutions

answered
User Palamino
by
7.8k points

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