asked 54.8k views
4 votes
Find the value of x to the nearest tenth.

Find the value of x to the nearest tenth.-example-1
asked
User Ndech
by
8.2k points

2 Answers

12 votes

Answer:

x = 57.8°

Step-by-step explanation:

  • opposite length : 11
  • hypotenuse length : 13


\sf sin(x)= (opposite)/(hypotensue)


\hookrightarrow \sf sin(x) = (11)/(13)


\hookrightarrow \sf x = sin^(-1)((11)/(13) )


\hookrightarrow \sf x = 57.8

answered
User IvanZh
by
9.0k points
5 votes

Answer:

57.8° (nearest tenth)

Step-by-step explanation:

Use the sine trig ratio:


\mathsf{\sin(\theta)=(O)/(H)}

where:


  • \theta is the angle
  • O is the side opposite the angle
  • H is the hypotenuse

Given:


  • \mathsf{\theta=x}
  • O = 11
  • H = 13


\implies \mathsf{\sin(x)=(11)/(13)}


\implies \mathsf{x=\arcsin(11)/(13)}


\implies \mathsf{x=57.8 \textdegree \ (nearest \ tenth)}

answered
User Art C
by
7.3k points

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