The x intercepts of the function f(x) = 2x(x-5)^2(x+4)^3 are

Question

asked May 7, 2022 4.3k views

2 Answers

Dkastl · Answer 1 · 2022-05-11T01:48:40+0000

Answer:

$\boxed{\sf x- intercepts = 0 , 5 \ and \ -4}$

Explanation:

A function is given to us and we need to find the x Intercepts of the graph of the given function . The function is ,

$\sf \implies f(x) = 2x( x - 5 ) ^2(x+4)^3$

For finding the x intercept , equate the given function with 0, we have ;

$\sf \implies 2x ( x - 5 )^2(x+4)^3= 0$

Equate each factor with 0 ,

$\sf \implies 2x = 0$

Divide both sides by 2 ,

$\sf \implies\bf x = 0$

Again ,

$\sf \implies ( x - 5)^2=0$

Taking squareroot on both sides,

$\sf \implies x - 5 = 0$

Add 5 to both sides,

$\sf \implies \bf x = 5$

Similarly ,

$\sf \implies \bf x = -4$

Hence the x Intercepts are -4 , 0 and 5 .

{ See attachment also for graph } .