Question

CT=x^2, CA=3x-4, and AT=4x-8, find the value(s) of x if A is between C and T

Answer 1

x = 3 and x = 4

Explanation:

3x - 4 + 4x - 8 = x^2

7x -12 = x^2

x^2 - 7x + 12 = 0

(-4)*(-3) = 12 and (-4)+(-3) = -7

(x-3)(x-4) = 0

x - 3 = 0. x = 3

x - 4 = 0. x = 4