Question

The minimum turning point

of a quadratic curve is (2,
-7).
Write an equation for this in
the form:
y=x^2+ax+b

Answer 1

Answer:a=-4, b=-3

Explanation:

Vertex is (2,-7)

`y=k(x-2)^2-7=k(x^2-4x+4)-7 =x^2+ax+b\ \Longrightarrow\ k=1\\\\y=x^2-4x-3\\\\a=-4\\b=-3\\`