Question

Suppose a= 1.885 and b= 3.572. Let θ be an angle in standard position that lies in Quadrant 3 with tan(θ)=ab. Find sec(θ). Round your answer to 3 decimal places.

Answer 1

9514 1404 393

Answer:

-1.131

Explanation:

The relationship between secant and tangent is ...

sec²(x) = 1 + tan²(x)

In the 3rd quadrant, the secant is negative, so the value is ...

sec(θ) = -√(1 +tan²(θ)) = -√(1 +(1.885/3.572)²) ≈ -√1.278483718

sec(θ) ≈ -1.131