asked 107k views
5 votes
If the 102,619 residents of a city are divided into 57 equal groups, then some residents don't fit into a group.

How many residents would be in each group?

How many residents would not fit into a group?

Enter your answers in the boxes.

asked
User JeffD
by
8.3k points

2 Answers

2 votes

Answer:

1800: residents in each group

019: residents not fitting into a group

Explanation:

57 divides into 102 one time.

57 divides into 456 eight times. Bring down the 1.

57 divides into 1 zero times. Write 0 in the quotient. Bring down the 9.

57 divides into 19 zero times. Write 0 in the quotient.

There are no more digits to bring down. The remainder is 19.

If the 102,619 residents of a city are divided into 57 equal groups, then some residents-example-1
answered
User Tarlog
by
9.1k points
3 votes

Answer:

1,800, 19

Explanation:

102,619÷57=1800 (nearest one)

102,619-1800×57=19

answered
User Ali Besharati
by
8.2k points
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