Question

How many grams of CuSO4 • 5H2O do you need to make 0.8 L of a 0.6 M solution

Answer 1

Understanding the concept:-

Here the concept of Molarity used .We will put the formula of Molarity then we find moles of copper sulphate .Then we can find the.Given weight of Copper sulphate.So let's do

Solution:-

• Volume of Solvent=0.8L
• Molarity=0.6M

We know

`\boxed{\sf Molarity=(Moles\:of\: solute)/(Volume\:of\: Solvent \:in\;L)}`

`\\ \rm\longmapsto Moles\:of\: solute=Molarity* Volume\:of\: Solvent\:in\:L`

`\\ \rm\longmapsto Moles\:of\: Solute=0.8(0.6)`

`\\ \rm\longmapsto Moles\:of\: Solute=0.48mol`

Now

Molar Mass of Solute:-

`\\ \rm\longmapsto CuSO_4.5H_2O`

`\\ \rm\longmapsto 65u+32u+4(16u)+5(2* 1u+16u)`

`\\ \rm\longmapsto 96u+64u+5(2+16)`

`\\ \rm\longmapsto 160u+90u`

`\\ \rm\longmapsto 250u`

`\\ \rm\longmapsto 250g/mol`

Now

`\boxed{\sf No\:of\:moles=(Given\:Mass)/(Molar\:Mass)}`

`\\ \rm\longmapsto Given\:Mass=No\:of\:Moles* Molar\:Mass`

`\\ \rm\longmapsto Given\:Mass=250(0.48)`

`\\ \rm\longmapsto Given\:Mass=120g`