Question

Find three consecutive odd numbers such that the sum of five times the smaller number and twic the larger number is 33 more than six times the median number

Answer 1

37, 39, and 41

Explanation:

let the numbers are A, (A+2), (A+4)

the equation could be :

5A + 2(A+4) = 33 + 6(A+2)

5A+2A+8 = 33 + 6A+12

7A+8 = 45+6A

7A-6A = 45-8

A = 37

so, the three odd numbers are :

37, 39, and 41