6+\sqrt[5]{249-2x} =7

Question

`6+\sqrt[5]{249-2x} =7`

Answer 1

x=124

Explanation:

`6+\sqrt[5]{249-2x} =7\\\sqrt[5]{249-2x} =7-6=1\\249-2x=1^5=1\\249-1=2x\\2x=248\\x=(248)/(2) =124`

Answer 2

Answer: 124

Explanation:

First, subtract 6 on both sides to get:

`\sqrt[5]{249-2x} =1`

Take both sides to the 5th power. The radical will cancel, and the right side will be unchanged:

`249-2x=1`

Subtract 249 on both sides:

`-2x=-248`

`2x=248`

`x=124`