Question

1+-w2+9w and I need help cuz I’m on 76 and I’m sooo close help

Answer 1

`\huge \boxed{\mathfrak{Question} \downarrow}`

• Simplify :- 1 + - w² + 9w.

`\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}`

`\large \sf1 + - w ^ { 2 } + 9 w`

Quadratic polynomial can be factored using the transformation
`\sf \: ax^(2)+bx+c=a\left(x-x_(1)\right)\left(x-x_(2)\right)`, where
`\sf x_(1) and x_(2)` are the solutions of the quadratic equation
`\sf \: ax^(2)+bx+c=0`.

`\large \sf-w^(2)+9w+1=0`

All equations of the form
`\sf\:ax^(2)+bx+c=0` can be solved using the quadratic formula:
`\sf\frac{-b±\sqrt{b^(2)-4ac}}{2a}`. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

`\large \sf \: w=\frac{-9±\sqrt{9^(2)-4\left(-1\right)}}{2\left(-1\right)} \\`

Square 9.

`\large \sf \: w=(-9±√(81-4\left(-1\right)))/(2\left(-1\right)) \\`

Multiply -4 times -1.

`\large \sf \: w=(-9±√(81+4))/(2\left(-1\right)) \\`

Add 81 to 4.

`\large \sf \: w=(-9±√(85))/(2\left(-1\right)) \\`

Multiply 2 times -1.

`\large \sf \: w=(-9±√(85))/(-2) \\`

Now solve the equation
`\sf\:w=(-9±√(85))/(-2)` when ± is plus. Add -9 to
`\sf√(85)`.

`\large \sf \: w=(√(85)-9)/(-2) \\`

Divide -9+
`\sf√(85)` by -2.

`\large \boxed{ \sf \: w=(9-√(85))/(2)} \\`

Now solve the equation
`\sf\:w=(-9±√(85))/(-2)` when ± is minus. Subtract
`\sf√(85)` from -9.

`\large \sf \: w=(-√(85)-9)/(-2) \\`

Divide
`\sf-9-√(85)` by -2.

`\large \boxed{ \sf \: w=(√(85)+9)/(2)} \\`

Factor the original expression using
`\sf\:ax^(2)+bx+c=a\left(x-x_(1)\right)\left(x-x_(2)\right)`. Substitute
`\sf(9-√(85))/(2)`for
`\sf\:x_(1)` and
`\sf(9+√(85))/(2)` for
`\sf\:x_(2)`.

`\large \boxed{ \boxed {\mathfrak{-w^(2)+9w+1=-\left(w-(9-√(85))/(2)\right)\left(w-(√(85)+9)/(2)\right) }}}`

NOTE :-

Well, in the picture you inserted it says that it's 8th grade mathematics. So, I'm not sure if you have learned simplification with the help of biquadratic formula. So, if you want the answer simplified only according to like terms then your answer will be ⇨

`\large \sf \: 1 + - w {}^(2) + 9w \\ =\large \boxed{\bf \: 1 - {w}^(2) + 9w}`

This cannot be further simplified as there are no more like terms (you can use the biquadratic formula if you've learned it.)