Question

an oil storage tank ruptures and oil leaks from the tank at a rate of r(t)= 100e^(-0.01t) liters per minute. How much oil leaks out during the first hour?

Answer 1

Explanation:

`\\\displaystyle V=\int\limits^(60)_0 {100*e^(-0.01*t)} \, dx \\\\=-(100)/(0.01) *\Bigg [e^(-0.01*t)\Bigg ]^(60)_0\\\\=-10000*(e^(-0.60)-1)\\\\=4511.883663.... (liters)`