asked 234k views
4 votes
If 5 is a root of the quadratic equation x²+4x-45=0 find the other root of the equation


asked
User Gitbox
by
8.1k points

2 Answers

5 votes

Answer:

-9

Explanation:

x² + 4x - 45

x² + (9x - 5x) - 45

x² + 9x - 5x - 45

x(x + 9) - 5(x + 9)

(x + 9)(x - 5)

x + 9 = 0

x = -9

answered
User Pierrebo
by
8.9k points
1 vote

Answer: -9

Explanation:

If 5 is a root of the quadric equation, then

x²+4x-45=0

x²-5x+9x-45=0

x(x-5)+9(x-5)=0

(x-5)(x+9)=0

The other root is -9

answered
User Ashil John
by
7.8k points

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