Answer:
Solution 
verified 
Verified by Toppr 
The radius of the tire is r=0.500m. The speed of the stone on its outer edge is 
 v 
t 
 
 = 
T 
2πr 
 
 = 
(60.0s/200rev) 
2π(0.500m) 
 
 =10.5m/s 
and its acceleration is 
 a= 
R 
v 
2 
 
 
 = 
0.500m 
(10.5m/s) 
2 
 
 
 =219m/s 
2 
 inward.
Step-by-step explanation: