$3√(578)-√(162)+4√(32)=\\\\=3√(289\cdot2)-√(81\cdot2)+4√(16\cdot2)=\\\\=3√(17^2\cdot2)-√(9^2\cdot2)+4√(4^2\cdot2)=\\\\=3\cdot17\sqrt2-9\sqrt2+4\cdot4\sqrt2=\\\\=51\sqrt2-9\sqrt2+16\sqrt2=51\sqrt2+7\sqrt2=\boxed{58\sqrt2}$

Alexandru Luchian answered Oct 29, 2022

Simplify 3√578 - √162 + 4√32

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