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Find the perimeter of a triangle if the three sides are
4x^2-x+4, 2x^2-2x+1, x^2+8x+3

asked
User Jinu P C
by
8.1k points

1 Answer

3 votes

Answer:

7x^2+5x+8

Explanation:

Perimeter = sum of all sides

Perimeter = 4x^2-x+4+2x^2-2x+1+x^2+8x+3

= 7x^2+5x+8

answered
User Martijn Burger
by
8.7k points

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