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Find the center of a circle with the equation: x^2+y^2-32x-60y+1122=0 A. (24, 30) B. (13, 20) C. (14, 28) D. (16, 30)

Find the center of a circle with the equation: x^2+y^2-32x-60y+1122=0 A. (24, 30) B. (13, 20) C. (14, 28) D. (16, 30)
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Find the center of a circle with the equation: x^2+y^2-32x-60y+1122=0

A. (24, 30)
B. (13, 20)
C. (14, 28)
D. (16, 30)

asked
User Slobo
by
7.6k points

2 Answers

4 votes

Answer:

-32x-60y+1122=0

-(32x+60y-1122)=0

32x+60y-1122=0

by factorize

answered
User Svick
by
8.3k points
4 votes

Answer:

24,30

Explanation:

answered
User Taylor Huston
by
7.8k points
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