Answer:
6 is the answer
Explanation:
Equation A: 
 
y=6x-b 
 
Equation B: 
 
-3x+1/2y= -3 
 
If the system of equation has infinite number of solutions then Equation A is equal to Equation B. 
 
We will take equation B and move all the values to the R.H.S and isolate variable y 
 
-3x+1/2y = -3 
 
1/2y= -3 +3x 
 
Multiply both sides by 2 
 
2 * 1/2y = 2(-3+3x) 
 
y = -6+6x 
 
y = 6x-6 ------- Equation B(I) 
 
Now equate Equation A and Equation B(I) 
 
6x-b = 6x-6 
 
Subtract 6x from both sides. 
 
6x-6x-b = 6x-6x - 6 
 
-b = -6 
 
Negative sign will be cancelled out by each other. 
 
b = 6