Question

Please help! x^3 +y^3=9

Answer 1

Explanation:

Taking the derivative of both sides with respect to x, we get

`(d)/(dx)(x^3 + y^3) = (d)/(dx)(3)`

`\Rightarrow 3x^2 + 3y^2(dy)/(dx) = 0`

Solving for
`(dy)/(dx)`, we get

`(dy)/(dx) = -(3x^2)/(3y^2) = -(x^2)/(y^2)`