Question

$10 bet between you and me. At any time during the game, I can ask to double it. If you accept we both put in another $10 and if you win, you win the $20 and if you lose, you lose it all. If you reject, you lose the initial $10. What is the minimum probability you would take to accept the double

Answer 1

66%

Explanation:

`-10x\:+\:\left(20\cdot \left(1-x\right)\right)=\:0`

x =
`(2)/(3)` = .666 = 66%