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4 votes
Given that ABCD is a rhombus, what is the value of x?

B
C.
(3x + 12)
D
A. 19.5
B. 78
C. 15.8
D. 26
E. 52
F. Cannot be determined

Given that ABCD is a rhombus, what is the value of x? B C. (3x + 12) D A. 19.5 B. 78 C-example-1

1 Answer

3 votes

Answer:

Diagonals of a rhombus intersect at right angles

Therefore,
\angle AOD=90


Now,in\: \bigtriangleup AOD


\angle OAD+\angle AOD+\angle ADO=180


x+90+3x+12=180
\leftarrow [combing \: like\: terms]


4x+102=180\\-102 \: -102
\leftarrow [subtracting \:102 ]


(4x)/(4) =(78)/(4) \leftarrow [dividing \: by\: 4]


x=19.5
\Longleftarrow

OAmalOHopeO

answered
User Njahnke
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