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8.50 g of a sample of iron required just 75 cm of 3.00 M HCl to dissolve it and give a neutral solution. Calculate the % purity of the sample of iron.​

8.50 g of a sample of iron required just 75 cm of 3.00 M HCl to dissolve it and give a neutral solution. Calculate the % purity of the sample of iron.​
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8.50 g of a sample of iron required just 75 cm of 3.00 M HCl to dissolve it and give a neutral solution. Calculate the % purity of the sample of iron.​

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User Ramiz
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1 Answer

4 votes

Answer:

Step-by-step explanation:

2HCl +Fe =FeCl2+H2

nHCl=0.225

nFe=0.225/2

H=74.12%

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User CatalystNZ
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