Question

Please help with this too

Answer 1

The area of the sector in circle G formed by segments
`\overline{AG}`, and
`\overline {GB}` is approximately 125.66 square units

Explanation:

The given parameters are;

The radius of the circle with center G, r = 15

The measure of the given angle, m∠AGB = 64°

The area of a sector is given as follows;

Area of a sector of a circle = (θ/360°) × π × r²

Therefore;

The area of the sector in circle G formed by segments
`\overline{AG}`, and
`\overline {GB}` is given as follows;

The area of the sector in circle G = (64°/360°) × π × 15² ≈ 125.66 square units