Question

Find the distance between (-5,5) and (2,-2)

Answer 1

The distance is 7
`√(2)`

Explanation:

Answer 2

`\huge\textsf{Hey there!}`

`\large\textsf{The formula for \underline{distance between} is: }\mathsf{√((x_2-x_1)^2 + (y_2 - y_1)^2)}`

`\large\textsf{Whereas }\mathsf{x_2}\large\textsf{ is }\mathsf{2}\large\textsf{ and }\mathsf{x_1}\large\textsf{ is }\mathsf{ -5}\\\\\large\textsf{And also }\mathsf{y_2}\large\textsf{ is }\mathsf{ -2}\large\textsf{ and }\mathsf{ y_1}\large\textsf{ is }\mathsf{5}`

`\mathsf{√((2 - -5)^2+ (-2 + 5)^2)}\\\mathsf{2 - -5}\\\mathsf{= 2 + 5}\\\mathsf{= \bf 7}\\\\\mathsf{-2 + 5}\\\mathsf{= \bf -7}\\\\\mathsf{= √((7)^2+ (-7)^2)}\\\\\mathsf{7^2}\\\mathsf{= 7*7}\\\mathsf{= \bf 49}\\\\\mathsf{(-7)^2}\\\mathsf{= -7*-7}\\\mathsf{= \bf 49}\\\\\mathsf{= √(49 +49)}\\\\\mathsf{49+49}\\\mathsf{=\bf 98}`

`\mathsf{= √(98)}\\\mathsf{= 7√(2)}`

`\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf 7√(2)}}}\huge\checkmark`

`\large\textsf{Good luck on your assignment and enjoy your day!}`

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`\frak{Amphitrite1040:)}`