What is the specific rotation of 13g of a molecule dissolved in 10 mL of solvent that gives an observed rotation of 23 degrees in a sample tube of 10 cm.

Question

asked Jun 6, 2022 185k views

1 Answer

Tylerlindell · Answer 1 · 2022-06-10T11:56:07+0000

Answer:

$\alpha=17.7$

Step-by-step explanation:

From the question we are told that:

Mass
m=13g

Volume
V=10mL

Angle
$\theta=23$

Sample Tube=10cm

Generally the equation for concentration is mathematically given by

C=m/v

$C=(13)/(10)\\C=1.3g/mL$

Therefore the Specific Rotation

$\alpha=frac{\theta }{m*l}$

$\alpha=frac{23 }{1.3*1.0}$

$\alpha=17.7$