Question

The product of 2 consecutive even integers is 16 less than 8 times their sum

Answer 1

there are two solutions:

x=0

and

x=14

Explanation:

lts suppose the numbers are x and x+2, so:

`x(x+2)=8(x+(x+2))-16\\x(x+2)=8(2x+2)-16=16x+16-16=16x\\x^2+2x=16x\\x^2-14x=0\\x(x-14)=0\\x=0,~x=14`