Question

What is the slope of a line that is perpendicular to the line joining point A(4, -1) and point B(3, 3)?

Answer 1

`m_1= (1)/(4)`

Explanation:

Given

`A = (4,-1)`

`B =(3,3)`

Required

Slope of line perpendicular to AB

First, we calculate the slope of AB using:

`m=(y_2 -y_1)/(x_2 -x_1)`

This gives:

`m=(3--1)/(3-4)`

`m=(4)/(-1)`

`m=-4`

The line perpendicular to AB has the following slope (m1):

`m_1= -(1)/(m)`

So, we have:

`m_1= -(1)/(-4)`

`m_1= (1)/(4)`