Answer:
The probability of selecting 2 Democrats and 2 Republicans is 29.36%.
Explanation:
Given that a city council consists of 7 democrats and 7 republicans, to determine, if a committee of 4 people is selected, the probability of selecting 2 Democrats and 2 Republicans must be performed the following calculation:
7/14 x 6/13 x 7/12 x 6/11 = X
0.5 x 0.46 x 0.58 x 0.54 = X
0.0734 = X
0.0734 x 100 = 7.34 x 4 = 29.36
Therefore, the probability of selecting 2 Democrats and 2 Republicans is 29.36%.