Question

Please click the photo and there are two questions to solve .Please help me guys

Answer 1

Explanation:

Distance formula:

`√((X_2-X_1)^2+(Y_2-Y_1)^2)`

Distance for AB

`√((4-2)^2+(1-(-5))^2)=√(4+36)=√(40)\\`

Distance for AC

`√((8-2)^2+(-3-(-5))^2)=√(36+4)=√(40)`

2.

same formula solve when positive

`5=√((6-3)^2+(y-2)^2)\\25=9+(y-2)^2\\16=(y-2)^2\\4=y-2\\6=y`

Now when it's negative

`5=√((6-3)^2+(y-2)^2)\\25=9+(y-2)^2\\16=(y-2)^2\\-4=y-2\\y=-2`

so y can equal 6 or -2