Question

Prove that
log a² - log b² = log (ab) log (a/b)​

Answer 1

Hope you could understand. Thank you.

If you have any doubt regarding this, feel free to ask.

Answer 2

Proof & Step-by-step explanation:

We know that log ab = log a + log b and log a/b = log a - log b, so we substitute that in and get (log ab)(log a/b) = (log a + log b)(log a - log b) = (log a)^2 - (log b)^2.

I hope this helps! If you have any questions, feel free to ask! :)