Answer:
a) 0.2347, 0.0007
b) 1.30 
c) 0.63
Explanation:
Given – 
Mean = 73.4 
Sigma = 4.7 
Probability that the speed is greater than 70 is 
P (X>70) = P (z> (70-73.4)/4.7) = P (z>-0.72) = 0.7653 
a) The probability that a car is not speeding = 1 - 0.7653 = 0.2347 
The probability that all 5 cars are not speeding = (0.2347)5 = 0.0007 
b) E (X) = 1/p = 1/0.7653 = 1.30 
c) Standard deviation = Sqrt (1-p/p) = (1-0.7653)/0.7653 = 0.63