Question

when measuring the radius of a sphere an error of 0.6% takes place in the measurement. What will be the permiable error while measuirng the surface

Answer 1

So, the error is
`4.8\pi r`.

Explanation:

Error in measuring the radius = 0.6 %

Let the radius is r.

The surface area of sphere is

`S= 4\pi r^2\\\\dS = 4 \pi* 2 r dr\\\\dS =8\pi r * 0.6 = 4.8\pi r`